Read Microsoft Word - 10.26.07 2nd printing correction.doc text version

October 25, 2006 Third Edition: Second Printing

Structural Concrete Theory and Design Corrections M. Nadim Hassoun / Akthem Al-Manaseer

Page 40: · · The second line after the equation (2.75): "Ecm28 "should be changed to " Ecmt0 " The "t" in the equation 2.76 should be changed to"t0".

The new equation should be:

Ecmt0 = Ecm 28 exp 0.5S 1 -

28 t0

Page 48: The third line from the bottom should be changed to:

RH = 1 +

1 - H /100 1 - 75 /100 1 2 = 1 + 0.836 0.950 = 1.415 3 h /4 0.16 e 0.16 3 76 / 4

Page 49: · Second line "1.419" should be changed to "1.415" and "1.678" to "1.674"

0 = RH ( f cm 28 ) (t0 ) = 1.415 × 2.49 × 0.475 = 1.674

· · Line 7: "1.678" should be changed to "1.674" and "0.515" to "0.514" Line 8: "0.515" should be changed to "0.514"

(t , t0 ) = 0 c (t , t0 ) = 1.674 × 0.307 = 0.514

Page 68: In figure 3.4, part (c)

and for the two cases: t 0.005 and not t < 0.005

Page 69: In table 3.1:

In the compression-controlled condition and under fy = 60 Ksi: t 0.002 and not t = 0.002

Page 87: In section 3.10: part (b): change "b" to "bw" in the equation of As.min, and the equation should be changed to:

As ,min

3 f c' 200 = bw d bw d fy fy

Page 92: Part 4: Calculate

a=

As f y 0.85 f 'c b

,c , t and 1

Page 98: In equation 3.49: add 1 and the equation should be changed to:

( - ') = 0.851

Page 123:

f c' fy

d' d

87 =K 87 - f y

In section 3.14: part 4. Add " 1" in the equation of K, and the equation should be changed to:

K = 0.851 ( f 'c / f y )(d '/ d )[87 /(87 - f y )]

Page 192: In section 6.2.5: part 2: · In part a; in the first line: concrete should be steel and the line should be changed to: a. Rectangular section with tension steel, As, only 2 · The equation 6.13 should be changed to : bx / 2 + (n - 1) A's (x - d') + nAs(d - x) = 0 3 2 2 · The equation 6.13a should be changed to : Icr = (bx / 3) + (n - 1) A's (x - d') + nAs(d - x) Page 206: In section 6.7: part 5: Equation 6.18:

s (in.) = 540 / f s - 2.5Cc but not greater than 12 (36 / fs) should be changed to:

But not greater than 12 (40 / fs)

s (in.) = 600 / f s - 2.5Cc

Page 206 to page 211: Pages are corrected and attached on the back of the file. Page 214: In Figure 6.14: Live load value should be changed from "1.4 K/ft (21KN/m)" to "1.33 K/ft (19.95 KN/m)". Page 263: In Design Summary (8.8): part 2 first line: "0.75" is missing. The equation should be changed to:

Vc = 0.75(2 f c' )bw d

Page 266: In example 8.2: figure 8.12: the number "13.94" should be changed to "12.94" Page 303: In example 9.3: · First line: "12 ft" should be changed to "11.5 ft" · Part 1: First line: "12" should be "11.5: and the line should be changed to: 11.5(12)/20 = 6.9 in. Assume a total depth of h = 7 in. and assume d = 6 in. (to be checked later). · Part 6: First line should be changed to: Check shear requirements: Vu at a distance d from the support is

0.409

11.5 6 - = 2.15 K 2 12

2

Page 321: In example 10.2: part 2: fifth line: "Use eight no. 10 bars" should be changed to: "Use eight no. 11 bars". Page 341: In equation 11.10: The equation should be changed to: Pn = Cc + Cs - T Page 357 & 359: In section 11.12: in both figure 11.16 and figure 11.17: in the last two lines in bottom of the pages the numbers should be changed: · (a) = 0.45 to = 0.6 · · (b) = 0.6 to = 0.7 (c) = 0.75 to = 0.8

Page 357 to 360: In section 11.12: figure 11.16 and figure 11.17 and in all charts: "ps" should be changed to "s" Page 371: In section 11.16.1:

·

The equation 11.28 should be changed to :

1 1 1 1 = + - Pu Pux Puy Puo

The part after equation 11.29 and after the word "where" add "factored" in the first four lines after the equal "=" sign. The four lines should be changed to: Pu = factored load strength under biaxial bending Pux = factored uniaxial load strength when the load acts at an eccentricity ey and ex = 0 Puy = factored uniaxial load strength when the load acts at an eccentricity ex and ey = 0 Puo = factored pure axial load when ex = ey = 0 Page 376: In example 11.18: · Part 1: in case b: last line the number "467.2" should be "476.2" The last line should be changed to: Pnx = 476.2 K Part 2: in case b: o In the seventh line should be equal to 0.65 and not 0.7 and the number "683.3" should be "683.8" and "478.7" should be "444.5" The seventh line should be changed to: Pny = Cc + Cs ­ T = 683.8 K, and Pny = Puy = 0.65 Pny = 444.5 K. o In the eleventh line Pnx should be Pny The last line of part b should be changed to: Pny = 444.5 K · Part 3: in third line: Pn should be Pno The last equation of the second line of part 3 should be changed to: Pno = 0.65 Pno = 1429 K ·

·

3

Page 431: In example 13.2: · Part 5: in fourth line: Vu2 should be Vu1 The equation should be changed to: Vu1 = 6.14 x (2.625) (10) = 161.2 K · Part 7: case b: in fourth line: the number "6.27" should be "6.67" The equation should be changed to:

A2 = 6.67 > 2 A1

Page 433: In example 13.3: · Part 4: in fourth line: The equation should be changed to:

12 1.5 19.5 - - × 6.02 × 8.5 = 185.5 K 2 2 12

Page 452:

Section e: part 1:

The equation should be changed to:

d11 =

Vu11 2 f 'c B

Page 590:

· In part 17.6: case 2; The first line should be changed to: For fm > 2.0, · Table 17.1: l l For fy = 60,000 psi, and without edge edge beams: n should be changed to n . 33 30

Page 591:

In lines 19 and 20: case 1 and 2: they should be changed to: 1. For slabs with fm < 2.0 : 5 in. 2. For slabs with fm > 2.0 : 3 1 in. 2

Page 786: Change the position of the title: "20.4.3 Seismic Force Effect, Em" from the middle of the page to line number 10 before the paragraph starting by: "Special seismic load combinations..." Page 789: Add in the figure 20.11 notes after " Areas of the flexural member where hoops are required": "These areas do not necessarily occur at midspan and not likely in buildings in high seismic zones".

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Microsoft Word - 10.26.07 2nd printing correction.doc

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